Rockbox Development > New Ports
iPod Classic and iPod Nano 3G, 4G
GodEater:
--- Quote from: pondlife on April 18, 2008, 01:38:04 AM ---No, it means that only one partition is exposed. If you could open your iPod and connect the disk to a native controller you might get a different result (or you might not).
--- End quote ---
And unless someone does that, we don't know the answer to the question :
--- Quote from: zajacattack ---Is the firmware for these versions stored in a separate (perhaps hidden?) partition like the earlier iPods and the Sansas?
--- End quote ---
boxerorange:
--- Quote from: pondlife on April 18, 2008, 01:38:04 AM ---
--- Quote from: boxerorange on April 17, 2008, 11:04:25 PM ---My guess would be that from my "fdisk -l"...scan(?) there's only one partition on my Classic.
--- End quote ---
No, it means that only one partition is exposed. If you could open your iPod and connect the disk to a native controller you might get a different result (or you might not).
pondlife
--- End quote ---
The partition exposed is 159.8gb, which leaves ~204mb left for Apple's Firmware. I'm guessing that would be plenty of space, considering that Rockbox (for 5g/5.5g) is under 10mb.
What do you mean by "connect to a native controller"? Actually connect the hard drive to a PC?
sexenox:
--- Quote from: boxerorange on April 19, 2008, 12:36:22 AM ---The partition exposed is 159.8gb, which leaves ~204mb left for Apple's Firmware. I'm guessing that would be plenty of space, considering that Rockbox (for 5g/5.5g) is under 10mb.
--- End quote ---
I'm not quite sure if this difference in size is caused by the 1000\1024^3 Bytes calculating problem? Or would the values differ even more in this case?
boxerorange:
--- Quote from: sexenox on April 19, 2008, 11:19:14 AM ---
--- Quote from: boxerorange on April 19, 2008, 12:36:22 AM ---The partition exposed is 159.8gb, which leaves ~204mb left for Apple's Firmware. I'm guessing that would be plenty of space, considering that Rockbox (for 5g/5.5g) is under 10mb.
--- End quote ---
I'm not quite sure if this difference in size is caused by the 1000\1024^3 Bytes calculating problem? Or would the values differ even more in this case?
--- End quote ---
how would that make any difference?
saratoga:
Instead of speculating, someone should check what the actual drive capacity is in bytes.
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